MIAMI, FL – Tallahassee is the least expensive destination in Florida based on the cost of its lodging, according to the latest survey from MiamiHotels.org.
Specifically, the survey established for 30 popular destinations in the state the average rate an overnight guest will have to spend for the cheapest available double room. The timeframe under consideration consists of the months of February and March, which represent the high season for the Sunshine State.
In Tallahassee, travelers will have to spend only $109 per night for the least expensive double room. That’s the lowest rate among all destinations considered. It must be noted that only such hotels located close to the city center/beach and rated at least 3 stars have been considered by the survey.
On the other end of the spectrum, Key West leads the ranking as the most expensive Floridian destination. With a nightly rate of $327 for the most affordable room, it is 200% more expensive than the state capital of Tallahassee. Also on the most expensive podium are Sanibel and neighboring Fort Myers Beach. Both are also boasting average rates well above $300 this late winter.
Downtown Miami ranks fifth most expensive in the state at an average price tag of $272 per night. Meanwhile, travelers to Miami Beach should find a room for around $200 per night. Also quite affordable are Orlando (Walt Disney World) and Jacksonville, with average rates of $122 and $126, respectively.
The following table shows the five most and five least expensive destinations in Florida based on the average rate for their cheapest available double room (minimum: 3-star hotel) during the time period spanning February 1 through March 31, 2016
1. Key West $327
2. Fort Myers Beach $315
3. Sanibel $312
4. Delray Beach $283
5. Downtown Miami $272
26. Jacksonville $126
27. Orlando (Walt Disney World) $122
28. Pensacola $121
29. Lakeland $115
30. Tallahassee $109